lets say no. of girls is x
total sum of ages of the class:
60 boys * 10.6 yrs + x girls * 10.1 years = (60 + x) * 10.5 years
or, 636 + 10.1x = 630 + 10.5x
or, 0.4x = 6
x = 6/0.4
no. of girls = 15
there are 12 boys in the class
Divide the number of girls by the total number of children (boys + girls).
The girls are 100% of the females and the boys are 100% of the males
There are 18 girls and 6 boys in the class of 24 students
45 noys
45 boys are in the class
87
yes there is difftrent class for boys and girls
there are 12 boys in the class
Divide the number of girls by the total number of children (boys + girls).
The girls are 100% of the females and the boys are 100% of the males
21 to 14
There are 18 girls and 6 boys in the class of 24 students
60% of the class
A fourth of the class are boys, which can be expressed as a fraction as 1/4. Since the class is made up of only boys and girls, and a fourth of the class are boys, the remaining part of the class must be girls. To find the fraction of the class that are girls, you can subtract 1/4 from 1. 1 - 1/4 = 3/4 So, 3/4 of the class are girls.
45 noys
It is not opssible to give a sensible answer to this question. 46+58 = 104. So if the class has 46% girls and 58% boys then the class has 4% who are simultaneously girls and boys.