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If seven times a number results in 35, then six times a number would be five less.
Oh, dude, so like, the difference between the product of six and a number and negative two times the number is essentially the same thing. You're just multiplying and subtracting in a different order. It's like saying "I have six apples and take away two apples" versus "I take away two apples and then have six left." Same outcome, different way of getting there.
It is 3*abs(n - 6) + 4*n
99,001
six less than fourteen times a number
Five times the difference of a number and six is the same as multiplying the difference of the number and six by five. This can be represented as 5(n-6), where n is the number.
If seven times a number results in 35, then six times a number would be five less.
It's an example of converting something easy into something nearly impossible, and then expressing it obscurely. Behind the veil lies an almost trivial algebra exercise. Although the question doesn't ask for the solution to the exercise, here it is anyway, at no extra cost: -- The difference between (eight times a number) and (twice the number) is (six times the number). -- (Six times the number) is eighteen. -- (the number) is one-sixth of eighteen, or three.
the difference of ten and six times a number
Oh, dude, so like, the difference between the product of six and a number and negative two times the number is essentially the same thing. You're just multiplying and subtracting in a different order. It's like saying "I have six apples and take away two apples" versus "I take away two apples and then have six left." Same outcome, different way of getting there.
It is 3*abs(n - 6) + 4*n
99,001
It is 90001.
6 + 5n < |n - 1| I have used the absolute value for "difference". This is, unfortunately, an ambiguous term. The absolute value is the difference between the numbers - irrespective of the sign.
The difference is four. Insects have six legs - birds only have two.
The difference between thirty six and four is thirty two.
100000 - 9999 = 90001