The four digits 6 7 8 and 9 can be arranged to form 24 different four digit numbers if these numbers are arranged from smallest to largest which number is in the seventeeth position?

Answer 1

First off, there are 6 arrangements that begin with 6, 6 that begin with 7, 6 that begin with 8, and 6 that begin with 9. This means the number begins with 8, since the number 8 begins all of the integers from positions 13 to 18. That gives you:

8 _ _ _

You do the same thing again, where 6 has the first two, 7 the middle two, and 9 the last two combinations, or those in position 17 and 18. We are now at

89 _ _

6 is the first one and 7 is the second out of the two numbers in positions 17 and 18, so the answer must be:

8967.

Answer 2

To determine the 17th number when the digits 6, 7, 8, and 9 are arranged from smallest to largest, we need to consider the permutations. The first digit will be 6, and the remaining digits 7, 8, and 9 can be arranged in 3! = 6 ways. This gives us a total of 6 permutations starting with 6. The next set of permutations will start with 7, and there will be 6 permutations for each starting digit. Therefore, the 17th number will be in the 3rd position of the permutations starting with 8. So, the number will be 6789.

Answer 3

Well, honey, if you arrange 6, 7, 8, and 9 from smallest to largest, the seventeenth number would be 6789. Simple math, darling. No need to complicate things.

Answer 4

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