Suppose the numbers are x and y and that x < y
Then y = 2x + 8
and x + y = 3y - 10
The second implies that x = 2y - 10
which, by the first gives x = 2(2x + 8) - 10 = 4x + 16 - 10
So -3x = 6 so that x = -2
and then y = 2*(-2)+8 = 4
So the two numbers are -2 and 4.
The larger number is 12.
13 and 6
The larger of two numbers is 8 more than 4 times the smaller if the larger number is increased by four times the smaller the result is 40. From this statement, we can calculate the values of the numbers where you get the value of the larger number to be 24 and that of the smaller number to be 4.
The larger one has exactly 9 times the area of the smaller one.
Does not exist. -------------------------------------------------------------------------------------------------------------- Whoever wrote this answer is as dum as a nut wastes excretion.
a=3b
The larger number is 12.
12 and 28
13 and 6
The numbers are: 3 and 12
The numbers are: 7 and 13
The larger of two numbers is 8 more than 4 times the smaller if the larger number is increased by four times the smaller the result is 40. From this statement, we can calculate the values of the numbers where you get the value of the larger number to be 24 and that of the smaller number to be 4.
101 and 26
Let the smaller number be ( x ). Therefore, the larger number is ( 3x ). According to the problem, ( x + 3x = 6 ), which simplifies to ( 4x = 6 ). Solving for ( x ) gives ( x = 1.5 ), and the larger number is ( 3 \times 1.5 = 4.5 ). Thus, the two numbers are 1.5 and 4.5.
x + y = 14 3x + 2y = 33 x = 5 y = 9
The smaller number is 9 . You should certainly be able to handle it from there.
To calculate how many times bigger one quantity is compared to another, divide the larger quantity by the smaller one. For example, if you have two numbers, A and B, where A is the larger number, you would calculate A ÷ B. The result tells you how many times larger A is compared to B. If the result is 3, then A is three times bigger than B.