The length of a rectangle is 9point7 cm more than 4 times the width If the perimeter of the rectangle is 91point4 cm what are its dimensions?

Answer 1

Suppose the width is W cm.

Then length, L = 4W + 9.7

Therefore, perimeter = 2*(4W + 9.7 + W) = 2*(5W + 9.7) = 10W + 19.4 cm

That is, 10W + 19.4 cm = 91.4 cm

Therefore, 10W = 91.4 - 19.4 = 72.0 cm

and so W = 7.2 cm.

Then L = 4W + 9.7 = 38.5 cm.

The rectangle is 7.2 cm x 38.5 cm