Two supplementary angles add up to 180 degrees. If one of the angles is x degrees, then the other angle will be 3x - 60. So we have: x + 3x - 60 = 180 4x - 60 + 60 = 180 + 60 4x = 240 4x/4 = 240/4 x = 60 3x - 60 = 3(60) - 60 = 120 Thus, the angles have measures of 60 and 120 degrees.
An angle and the angle that it is supplementary to have a total measure of 180 degrees.Let x be the supplementary angle. 4x would be the original angle.x + 4x = 1805x = 180x = 364x = 144So the two angles are 144 degrees and 36 degrees.
Let the angle be A, then the supplementary angle is (180 - A) and the complementary angle is (90 - A). But, 180 - A = 10(90 - A) = 900 - 10A 9A = 720 A = 80° The supplementary angle = 100° and the complementary angle = 10°
explement of the angle or conjugate of an angle
The angles are supplementary ===> A + B = 180 ===> A = 180 - B. Next statement: 3A = 2B - 5 (We don't know or care yet which one is larger, nor do we need to. That will come out on its own.) Substitute the first into the second: 3(180-B) = 2B-5 ===> (540-3B) = (2B-5 ) ===> 540 = 5B-5 ===> 545 = 5B109 = B ===> 71 = A
The angles are: 65 degrees and 115 degrees = 180 degrees
An angle and the angle that it is supplementary to have a total measure of 180 degrees.Let x be the supplementary angle. 4x would be the original angle.x + 4x = 1805x = 180x = 364x = 144So the two angles are 144 degrees and 36 degrees.
Let the angle be A, then the supplementary angle is (180 - A) and the complementary angle is (90 - A). But, 180 - A = 10(90 - A) = 900 - 10A 9A = 720 A = 80° The supplementary angle = 100° and the complementary angle = 10°
Angle 'A' is 7 more than 3 times angle 'B': A = 3B + 7 The angles are supplementary: A + B = 180 or A = (180 - B) (180 - B) = 3B + 7 180 = 4B + 7 173 = 4B B = 43.25 degrees A = 136.75 degrees Their difference is 93 degrees.
The angle= 36, the supplement= 144, the compliment=54
explement of the angle or conjugate of an angle
Supplementary angles add up to 180°. T - 35 = 4(180 - T) = 720 - 4T 5T = 720 + 35 = 755 T = 151° and its supplementary angle is therefore 29°.
The angles are supplementary ===> A + B = 180 ===> A = 180 - B. Next statement: 3A = 2B - 5 (We don't know or care yet which one is larger, nor do we need to. That will come out on its own.) Substitute the first into the second: 3(180-B) = 2B-5 ===> (540-3B) = (2B-5 ) ===> 540 = 5B-5 ===> 545 = 5B109 = B ===> 71 = A
x is the angle you're looking for and 3x is the angle that when added to x must total 180 degrees. Therefore the angle is 45degrees (x + 3x = 180)
Complimentary angles are ones that add to 90° Supplementary angles are ones that add to 180° Translate: The measure of a supplement of an angle (180-x) is (=)8 more (8+) than three times (3*) the measure of a complement (90-x). Find the measure of the angle? 180 - x = 8+3(90-x) 180 - x = 8 + 270 - 3x 180 - x = 278 - 3x - x = 98 - 3x 2x = 98 x = 49 Check: The measure of the supplement (131) is 8 more than 3 times the compliment (41) 41 * 3 + 8 = 131 123 + 8 = 131 ■
20o & 160o
15°
Suppose the angle is x then the second is 5x. The two angles are supplementary so x + 5x = 180 or 6x = 180 so that x = 30 degrees.