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320 meters squared.

Q: The perimeter of a rectangle is 72m the width of the rectangle is 16m what is the area of the rectangle?

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The answer is 320 square metres

Sum of the sides ie 8+8+3+3 = 22m. p=2l+2w thus, p=2(8m)+2(3m) p=16m+6m p=22m so the perimeter is 22m. yrevoj.

It is 16m, the middle value.

Kool i am in grade 9 too . . . what kind of questions are you looking for ? ? at the hardware store , the family purchases a fence that comes in 1 m sections. they purchase 16m of fencing . now they want to consider various dimensions for the dog's outdoor play area i need to find the length n width n the area

The base of this triangle would be 18 meters. One half*18 meters*16 meters= 72 square meters, this is the area of a triangle formula.

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The answer is 320 square metres

32m2 = 2m x 16m(width)Length(a) x width (16m) = 288m2288m2 / 16m = 18m

The perimeter of the rectangle is the sum of all four side lengths. A rectangle has two pairs of congruent sides. Two sides are 8m each. That accounts for 16m of the perimeter. 22 - 16 = 6. So the other two sides must add up to 6m. Divide that amount in half since the sides are congruent. The width of the rectangle is 3m.

Assuming you're measuring a rectangle... Okay - you know the length of one side (10m), and the perimeter (36m) The two sides you know total 20m, therefore the sum of the other two sides MUST equal 16m divided by 2 = 8m.

16m

Sum of the sides ie 8+8+3+3 = 22m. p=2l+2w thus, p=2(8m)+2(3m) p=16m+6m p=22m so the perimeter is 22m. yrevoj.

Area = 4 * 4 =16m²

This is not an equilateral triangle if height is 4 m the base is 6 m and by Pythagorean theorem the other sides are 5 m perimeter is 6 + 5 + 5 = 16m Area = base x height = 6 x 4 = 24 sq m

Height is 2m

It is 16m, the middle value.

If it is an isosceles triangle then side BC is 15cm and side AC is 15m

16m-10m = 6