No, but it can be multiplied: The new matrix is 3x3. EG: 100100 100 200 010010 x 010 = 020 001001 001 002 100 010 001
001, 002, 003, 004, 005, 010, 011, 012, 013, 014, 015, 020, 021, 022 and 023.
The smaller the value the closer it is to zero..003 < .01, therefore .003 is closer to zero.On a number line (not to scale):---(0)--(.001)-(.002)-(.003)-(.004)-(.005)-(.006)-(.007)-(.008)-(.009)-(.010)-(.011)Notice how .003 is closer to 0 than .010
.001
0.000 001 is one millionths.0.000 001 is one millionths.0.000 001 is one millionths.0.000 001 is one millionths.
Perfect on 001, good on 010.
After the Webmineral site the cleavage is: {100} Perfect, {010} Perfect, {001} Perfect.
No, but it can be multiplied: The new matrix is 3x3. EG: 100100 100 200 010010 x 010 = 020 001001 001 002 100 010 001
it has cubic cleavage, means perfect in {100}, {010}, {001} planes.
The cleavage of sodium chloride crystals is {100} Perfect, {010} Perfect, {001} Perfect.
input: 76543210(8) output: 111 110 101 100 011 010 001 000(2)
To convert a binary number to an octal number, you need to know how an octal number is represented in binary. It is like this: 0 = 000 4 = 100 1 = 001 5 = 101 2 = 010 6 = 110 3 = 011 7 = 111 As you can see, an octal number consists of 3 'bits' (either a 0 of a 1). Now, to convert a binary number to an octal number, you first have to group the binary digits into groups of 3 bits (starting from the right). Then, you convert every group of bits into octal numbers. This way you get your binary number into an octal one. For example: (1010100111010010)2 We group them into groups of 3 bits, starting from the right. 1 010 100 111 010 010 As you see, we have a single digit left. We must add 0's to make it a group of 3 bits. 001 010 100 111 010 010 Then we convert every group into an octal number, according to the table above. 001 = 1 010 = 2 100 = 4 111 = 7 010 = 2 010 = 2 And in this way, you converted a binary number into an octal one. (1010100111010010)2 = (124722)8
001, 002, 003, 004, 005, 010, 011, 012, 013, 014, 015, 020, 021, 022 and 023.
Each digit represents 3 bits. 0 = 000 1 = 001 2 = 010 3 = 011 4 = 100 5 = 101 6 = 110 7 = 111
The smaller the value the closer it is to zero..003 < .01, therefore .003 is closer to zero.On a number line (not to scale):---(0)--(.001)-(.002)-(.003)-(.004)-(.005)-(.006)-(.007)-(.008)-(.009)-(.010)-(.011)Notice how .003 is closer to 0 than .010
.001
001 = one