there are no real answers to an even root (2,4,6,8) of any negative number. the innovation of i allows you to find the unreal answers. i= the fourth root of positive 16 is 2. so, the roots of -16 are positive and negative 2i. post script: you cannot have a real even root of a negative because a negative multiplied by a negative turns into a positive.
2 and -2.
The real ones are -5 and +5.
If "a" is positive, it will have two fourth roots, one will be positive and one will be negative it will have one fifth root, which will be positive. If "a" is negative, it will have one fourth root, which will be negative. it will have one fifth root, which will be negative.
The 4th root of 256 is 4
The rule you can use is that root(a) x root(b) = root(ab), or root(a) / root(b) = root(a/b). This rule works for real numbers, but if you ever have to handle complex numbers, it is no longer valid. In the case of real numbers, it also works with cubic roots, fourth roots, etc.
The real fourth roots are -0.3 and 0.3
In general, the answer is 4, but only 2 of them are real. For example, the 4th roots of 16 are 2, -2, 2i, and -2i.
The answer will depend on the form of the fourth root. Positive real numbers will have two fourth roots which are real and two that are complex. Complex numbers will have four complex roots. However, none of these can be "simplified" in the normal sense of the term.
5 and -5
2 and -2.
The real ones are -5 and +5.
The fourth square root is the 16th root of a number. On a computer, to find the 16th root of a number, say 5.6, enter 5.6^(1/16). If the number you start with is positive, you will have 2 real roots (one positive and one negative) and 14 complex roots. If it is negative, you will have 16 complex roots.
Upto 4. If the coefficients are all real, then it can have only 0, 2 or 4 real roots.
If "a" is positive, it will have two fourth roots, one will be positive and one will be negative it will have one fifth root, which will be positive. If "a" is negative, it will have one fourth root, which will be negative. it will have one fifth root, which will be negative.
2i, which isn't real, but only possible answer.
There are 3 cube roots of 27. There are 2 square roots of 27 ( or any real number ). There are 4 fourth roots of 27 and so on:)
The 4th root of 256 is 4