13 + T >= 24 T >= 11 T is at least 11.
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8t
s(8+t)
4t = 24 Therefore t = 24/4 t = 6
62 + t
There are infinitely many common multiples of 24 and 4. Those are all numbers of form t = 24n, where n = 1, 2, 3, ..., because 24 itself is divisible by 4. The least common multiple of 4 and 24 is 24.