2 Numbers are a and b. We have( a>b) a+b=40(1) and a-b=10(2) a=10+b( from 2. Subtracts both side by b) => 10+b+b=40 (from 1. Substitute a with 10+b) => 10+2b =40 => 2b =30 => b =15 =>a=10+15=25 => a=25 b=15.
The sum of the numbers 1 to 39 = 39 x 40 ÷ 2 = 780 The sum of the numbers 1 to 60 = 60 x 61 ÷ 2 = 1830 Therefore the sum of the numbers 40 to 60 = 1830 - 780 = 1050
The two numbers are 10 and 2
9 13
0.4 and 2.
25 and 15
2 Numbers are a and b. We have( a>b) a+b=40(1) and a-b=10(2) a=10+b( from 2. Subtracts both side by b) => 10+b+b=40 (from 1. Substitute a with 10+b) => 10+2b =40 => 2b =30 => b =15 =>a=10+15=25 => a=25 b=15.
The sum of two numbers witha difference of two equals forty can be set up and solved this way: x + (x - 2) = 40 2x - 2 = 40 2x = 42 x = 21 x - 2 = 19 The two numbers are 21 and 19.
8 and 6 have a difference of 2 and a sum of 14.
The sum of the numbers 1 to 39 = 39 x 40 ÷ 2 = 780 The sum of the numbers 1 to 60 = 60 x 61 ÷ 2 = 1830 Therefore the sum of the numbers 40 to 60 = 1830 - 780 = 1050
The two numbers are 10 and 2
The numbers are 11 and 10
Sum of numbers = 40 Count of numbers = 4 Average = Sum/Count = 40/4 = 10
Three
24,26
9 13
0.4 and 2.