The numbers are 57, 59, 61 and 63.
The numbers are 57, 59, 61 and 63.
The sum of three consecutive odd numbers must be divisible by 3. As 59 is not wholly divisible by 3 the question is invalid. PROOF : Let the numbers be n - 2, n and n + 2. Then the sum is 3n which is divisible by 3. If the question refers to three consecutive numbers then a similar proof shows that the sum of these three numbers is also divisible by 3. Again, the question would be invalid.
59 and 61 consecutive numbers are basicly numbers that lie next to each other.Since 59 is right before 60 and 61 is right after 59,61 are consicutive to 60.
The sum of the first 60 positive integers (1 + 2 + 3 + .... + 59 + 60) is equal to 1830.
The numbers are 57, 59, 61 and 63.
The numbers are 57, 59, 61 and 63.
The numbers are 57 and 59.
The sum of three consecutive odd numbers must be divisible by 3. As 59 is not wholly divisible by 3 the question is invalid. PROOF : Let the numbers be n - 2, n and n + 2. Then the sum is 3n which is divisible by 3. If the question refers to three consecutive numbers then a similar proof shows that the sum of these three numbers is also divisible by 3. Again, the question would be invalid.
For 216 the numbers are 70, 72 and 74. For 238 the numbers are 58, 59, 60 and 61.
The two consecutive numbers which when added equal 59 are 29 and 30.
which three prime numbers have a sum of 59
To work this sort of problem out we need to divide the number given by the number of integers being sought (in that case two) 118 ÷ 2 = 59. So the two numbers will average 59 and they must be consecutive and even, that means that they must be 1 above and 1 below 59..... 58 and 60. 58 + 60 = 118
59
Oh, dude, the two numbers with a sum of 59 are 29 and 30. I mean, it's like basic math, right? Just add them up, and boom, you get 59. It's not rocket science, unless you're like a math astronaut or something.
58, 59, 60
The numbers are 59, 60 and 61.