Let's denote the three numbers as x, y, and z. From the information given, we have the following equations: x + y + z = 10 xyz = 30
To find the specific numbers, we can solve this system of equations. One possible solution is x = 3, y = 5, and z = 2. These numbers satisfy both conditions: their sum is 10, and their product is 30.
31
The numbers are 9, 10 and 11 with a sum of 30.
26
5+5 = 10 (Sum is ten)5*5 = 25 (Product is 25)*this product is maximum for all any 2 real numbers that == 10
the product of 8 and the sum of 10 and -7
the sum of 10 and the product of 7 and a number 2+5=7 2*5=10
There are no two numbers whose product is 23 and whose sum is 10. 23 is a prime number, and the only numbers whose product is 23 are 23 and 1. A prime number can only be divided by itself and 1.
It is 0.5
31
The numbers are 9, 10 and 11 with a sum of 30.
3 and 7 are the prime numbers because they cannot be divided by any number other than themselves and 1because 3+7 = 10 (Sum)and 3x7 = 21 (Product)
The numbers are: -10 and -8
There are no numbers, other than 23 and 1 whose product is 23. It is a prime number. There are many numbers whose sum is 10: 9+1, 8+2, 7+3, 6+4, 5+5, etc.
7x + 10
10 and 7
2 and 10
26