The sum of any number and 0 is the original number.
... itself.
Depends what the number is. If you were multiplying and did (substitute Z with any number)0xZ,the answer would always be zero. Actually the SUM is the answer to a addition problem. So the answer would be the number in which is to 0.
Would be that number. Example: 7+0= 7 0+7=7
The Identity Property of Addition.
This is due to the additive identity property: x + 0 = x. 0 simply does not change the value of any number when added (or subtracted).
Not necessarily. If the number is 0, then the sum of 8 times the number and -192 is -192.
Depends what the number is. If you were multiplying and did (substitute Z with any number)0xZ,the answer would always be zero. Actually the SUM is the answer to a addition problem. So the answer would be the number in which is to 0.
Would be that number. Example: 7+0= 7 0+7=7
The Identity Property of Addition.
I assume you mean the additive inverse. The sum of any number and its additive inverse is zero. For example, 7 + (-7) = 0.
The proposition is not true.pi and -pi are both irrational. But their sum, = 0, is rational.
It can be any number in the range (0, 360) degrees.between
Number + additive inverse of number = 0, by definition (the additive inverse of a number is that number, which when added to the original number, results in a sum of 0) Number + additive inverse of number = 0, by definition (the additive inverse of a number is that number, which when added to the original number, results in a sum of 0)
7
This is due to the additive identity property: x + 0 = x. 0 simply does not change the value of any number when added (or subtracted).
Any number multiplied by zero will always give the result of zero.
#include<iostream> unsigned sum_of_digits(unsigned num) { unsigned sum = 0; do { sum += num%10; } while (num/=10); return sum; } int main() { unsigned number = 12345; unsigned sum = sum_of_digits (number); std::cout << "Sum of digits in " << number << " is " << sum << std::endl; }
No, those are the only numbers that satisfy the equation. x squared -2x = 0