5+6+7=18
Consecutive even numbers that sum to thirty-eight (38) are eighteen (18) and twenty (20). Twenty (20) is larger than eighteen (18).
There is no solution. For X + (X+1) = 18, 2X = 17 and the answer is not an integer. (8.5)---------But for two consecutive even integers equal to 18 :X + (X+2) = 18 , 2X = 16 and the numbers are 8 and 10.
The middle number must be one third of 54 ie 18 so the other numbers are 17 and 19.
The numbers are 18, 19, 20, 21 and 22.
The numbers are 18 and 20.
The numbers are 5, 6, and 7.
14, 16 & 18
5 + 6 + 7 = 18 Consecutive numbers means numbers following one another in sequence.
The numbers are -18, -16 and -14.
The numbers are 17 and 18.
The numbers are -18 and -17.
Since 57/3 = 19, we know that the middle number has to be 19. The other numbers will be the numbers contiguous to 19. Therefore, the three consecutive numbers which add up to 57 are: 18 + 19 + 20 = 57
The consecutive numbers that add up to 16 are 5, 6, and 7. When you sum these three numbers (5 + 6 + 7), the total equals 18. However, if you are looking for two consecutive numbers, 7 and 8 can be considered, as their sum is also 15, which is close to 16. If strictly looking for combinations that total 16, the sequence would not consist of consecutive integers, as the closest pairs do not sum to exactly 16.
17, 18, and 19
18, 19, 20
18
The numbers are 17, 18, 19, 20 and 21.