Half of 154 is 77, so your numbers are 76 and 78.
The sum of -80 and 77 is -3
231 / 3 = 77So 76 + 77 +78 = 23177
16,25,36 add to 77. They are the squares of consecutive numbers 4,5,6
The answer is 53 and 24.
Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.
Divide the sum of the three consecutive odd integers by 3: 225/3 = 75. The smallest of these integers will be two less than 75 and the largest will be two more than 75, so the three consecutive odd integers will be 73, 75, and 77.
Half of 154 is 77, so your numbers are 76 and 78.
They are: 75+76+77 = 228
4, 5 & 6 (16 + 25 + 36)
The numbers are 38 and 39.
If: 3x+2x = 77 Then: 5x = 77 => x = 15.4 The numbers which are not integers are: 46.2+30.8 = 77
240
77 is between the integers 76 and 78.
Which two integers is the irrational number √77 between?
The only positive integers that make a product of 154 are: 77, 2 22, 7 11, 14 None of these add up to 28. 77+2=79 22+7=29 11+14=25
The first integer must equal 77 - 69 = 8 , since doubling it increases the sum by this amount. Similarly, the second integer must = 91 - 69 = 22. Then the third integer is 69 - 22 - 8 = 39.