4 and -7; 4 + -7 = -3 and 4 - (-7) = 4 + 7 = 11
-- write the difference between the integers without regard to their signs -- give the difference the same sign as the larger of the two integers
When the integers are negative.
8 and -8; 8 + (-8) = 8 - 8 = 0, and 8 - (-8) = 8 + 8 = 16
if you were to do it as a fraction the two integers would be 1 and a half. your welcome:] !!!
1 and 0 are the two whole numbers with their sum same as their difference
No, the sum of two integers is not equal to the difference of the same two integers, except in specific cases. For two integers ( a ) and ( b ), the sum is ( a + b ) and the difference is ( a - b ). These two expressions can only be equal if one of the integers is zero or if they are equal (i.e., ( a = b )). In general, the sum will be greater than or less than the difference, depending on the values of ( a ) and ( b ).
7 and -4
-- Their sum and difference both have the same sign that the two integers have. -- Their product and quotient are both positive.
-- write the difference between the integers without regard to their signs -- give the difference the same sign as the larger of the two integers
When the integers are negative.
The product of the two integers is -80.
The integers are -7 and -5.
Yes, by definition, the sum of two integers is always an integer. Likewise, the product and difference of two integers is always an integer.
8 and -8; 8 + (-8) = 8 - 8 = 0, and 8 - (-8) = 8 + 8 = 16
The two integers are -4 and 7.
90
Three and Five.