To be divisible by both 4 and 9 a number must be a multiple of the Least Common Factor of 4 and 9. The LCM is 36.
The first 3 digit number in each hundred that is a multiple of 36 are as follows :-
108, 216, 324, 432, 504, 612, 720, 828 and 900.
what is the largest three-digit number that is divisible by 4, 5, and 6
The highest six-digit number divisible by 3, 4, and 5 is 999960.
If the last two digits are divisible by 4 then the number is divisible by 4. Thus, if the tens digit is even and the units digit is 0 or 4 or 8 OR if the tens digit is odd and the units digit is 2 or 6 then the number is divisible by 4.
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
1002 is the smallest 4 digit number divisible by 3 and 2.
what is the largest three-digit number that is divisible by 4, 5, and 6
To get the three number that is divisible by 4 you will take the difference 4^3 and 4^2.
300
300
996
The highest six-digit number divisible by 3, 4, and 5 is 999960.
100 is the lowest three diget number divisible by 4.
108
If the last two digits are divisible by 4 then the number is divisible by 4. Thus, if the tens digit is even and the units digit is 0 or 4 or 8 OR if the tens digit is odd and the units digit is 2 or 6 then the number is divisible by 4.
There is no 4-digit number that is divisible by 2356 and 10.
smallest 4-digit number divisible by 2 = 1000
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.