The number is 7.
One.
3(x+21) = 2(x+23)3x+63=2x+46x=-17
The number required is 2/3 because 3*(2/3)+2*(3/2) = 5
7
a=58.4615 b=5.2308 c=41.3076
One.
3(x+21) = 2(x+23)3x+63=2x+46x=-17
The number required is 2/3 because 3*(2/3)+2*(3/2) = 5
5
10
"The sum of a number and three times another number is 18. find the numbers if their product is a maximum?"
Thirty decreased by three times a number is six less than three times the number. Find the number.
7
-3
18, 20 and 22
Their sum is three times the middle number.
Is this exactly how the problem was written?