You would need two 3 cm squares and two 2 cm squares to get a total area of 35 sq cm. A 3 cm square has an area of 9 sq cm and a 2 cm square has an area of 4 sq cm.
A cone with the radius of 5 cm and slope height of 9 cm has a total surface area of approximately 219.91cm2
A square with a side length of 2 cm has an area of 4 square cm
8 cm Check: 2(5*6) + 2(5*8) + 2(6*8) = 236 cm2 Solved by using algebra.
Area of ANY circle is (pi) x (radius)2 .
Assuming that the shape is triangular, the area is approx 1139 cm^2.
You would need two 3 cm squares and two 2 cm squares to get a total area of 35 sq cm. A 3 cm square has an area of 9 sq cm and a 2 cm square has an area of 4 sq cm.
Total surface area of cylinder: (2*pi*4.5^2)+(9*pi*13) = 495 square cm rounded
Total surface area = (2*pi*62)+(12*pi*15) = 791.681 square cm to 3 d.p.
Total surface area = (pi*32) + (2*pi*3*6) = (2*pi*32) = 63*pi square cm The height of the cylinder has to be 6 cm because the radius of the hemisphere is 3 cm which is also its height.
A circle with a radius of 2 cm has an area of 12.57 square cm.
A cone with the radius of 5 cm and slope height of 9 cm has a total surface area of approximately 219.91cm2
51 cm 45cm 72.1 cm
To find the dimensions of a square with an area of 4 cm^2, you need to take the square root of the area. In this case, the square root of 4 is 2. Therefore, the side length of the square is 2 cm. Since a square has all sides equal, the dimensions of the square with an area of 4 cm^2 would be 2 cm x 2 cm.
A square with a side length of 2 cm has an area of 4 square cm.
Total surface area = 4*4*6 = 96 square cm
Trapezoid Area = (1/2)(b1 + b2)(h) We have: b1 = 6cm b2 = 8 cm h = 5 cm Substitute the given values into the area formula: Trapezoid Area = (1/2)(b1 + b2)(h) Trapezoid Area = (1/2)(6 cm + 8 cm)(5 cm) Trapezoid Area = (1/2)(14 cm)(5 cm) Trapezoid Area = (7 cm)(5 cm) Trapezoid Area = 35 cm^2