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If cos B is 5/13, find sin B, tan B, sec B, and cot B?

sin= y/r= 12/13
cos= x/r= 5/13
tan= y/x= 12/5
csc= r/y= 13/12
sec= r/x= 13/5
cot= x/y= 5/12

x2+y2=r2

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Q: Trigonometry help please
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