For a sum = 12, there's only one (6 + 6), 1/36
For a sum = 4, there's three: 2/36 (1 + 3) + 1/36 (2 + 2) = 3/36
The answer depends on what numbers are on the faces of the dice.
If they are normal dice, the probability is 0.
3/6 chance of an odd number with one roll of the dice and 3/6 for the second roll of a dice so 3/6 x 3/6 = 9/36 = 3/12 = 1/4 there is a one in four chance that two odd numbers will be rolled from two roles of a dice.
The probability is 1 and you do not need Matlab to get that answer - only a little bit of thought.
The probability of rolling a composite number on a 6 sided die, numbered 1, 2, 3, 4, 5, and 6, is 1 in 3. There are two composite numbers on the die, 4 and 6. The others are prime, 2, 3, and 5, or unity, 1, so there are 2 possible outcomes in an possible result set of 6, hence the probability is 2 in 6, or 1 in 3.
It depends on the numbers on the 4 sided die. I don't believe that is a recognised standard.
If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.
The first dice can show any of the eight numbers. If the dice are to show different numbers the second dice has 7 different numbers out of a possible 8 to chose from. So the probability is 7/8 or 0.875 or 87.5% chance.
3
The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.
It is 1/6.
one in sixsame for any number
It's1/12
Half the numbers are odd on each die. (1 - (0.5 * 0. 5)) = 0.75
1/9
You can't get 14 with two regular six-sided dice ! The highest you can get with one throw is 12.
The probability is 1, if the dice are rolled often enough.