The integers are 24, 25 and 26.
6
7 23 + 25 + 27 = 75. The largest of these 3 integers is 27.
If sum were 75 the integers would be 24, 25 and 26, so the next lowest sum would be 23 + 24 + 25 ie 72. The answer is thus 23.
Let's represent the two consecutive numbers as x and x+1. The sum of these two numbers is x + (x+1) = 2x + 1. Given that the sum is 75, we have the equation 2x + 1 = 75. Solving for x, we find x = 37. Therefore, the two consecutive numbers are 37 and 38, and their sum is indeed 75.
Divide the sum of the three consecutive odd integers by 3: 225/3 = 75. The smallest of these integers will be two less than 75 and the largest will be two more than 75, so the three consecutive odd integers will be 73, 75, and 77.
37 and 38
24 + 25 + 26 = 75
37 and 38 are the only ones.
The integers are 24, 25 and 26.
6
7 23 + 25 + 27 = 75. The largest of these 3 integers is 27.
They are 24, 25 and 26, as well as the consecutive odd integers 23, 25 and 27.
* 71 * 73 * 75
They are: 75+76+77 = 228
23, 25, 27.
The integers are 24, 25 and 26.