The integers are 24, 25 and 26.
6
7 23 + 25 + 27 = 75. The largest of these 3 integers is 27.
The two consecutive integers between which the square root of 75 lies are 8 and 9. 82 is 64 and 92 is 81.
If sum were 75 the integers would be 24, 25 and 26, so the next lowest sum would be 23 + 24 + 25 ie 72. The answer is thus 23.
Divide the sum of the three consecutive odd integers by 3: 225/3 = 75. The smallest of these integers will be two less than 75 and the largest will be two more than 75, so the three consecutive odd integers will be 73, 75, and 77.
37 and 38
24 + 25 + 26 = 75
37 and 38 are the only ones.
The integers are 24, 25 and 26.
6
7 23 + 25 + 27 = 75. The largest of these 3 integers is 27.
They are 24, 25 and 26, as well as the consecutive odd integers 23, 25 and 27.
* 71 * 73 * 75
They are: 75+76+77 = 228
The integers are 24, 25 and 26.
23, 25, 27.