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You can easily see the trapezium is symmetrical.

Draw a vertical line starting where upper 14m line ends downwards.

Consider the triangle you got now. It's a right triangle, with one leg 3m (20-14/2) long and hypotenuse 6m long.

Ratio of that leg to hypotenuse is a/c = 0.5 = cos angle

To find angle, you have to find a value of angle for which cosine equals 0.5 (use arccosine function).

However if you look at trigonometry tables for most common angles, you can easily see its 60 deg.

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Q: Two parallel sides of the trapezium are 14m and 20m and the other sides are both 6m. What would be the angle between the 20m parallel side and the 6m other side And how did you work it out?
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