Impossible if only adding :/
1+9=10
2+8=10
3+7=10
4+6=10
5+0=5
10*4=40
40+5=45
-9
-9
3 addends mean 3 numbers. Regroup I believe means carry over. So I'm thinking something like 36+29+12=
i dont understand the question . sorry!and please make it more understangable. its just numbers. sorry once again!
1+2+3+4+5+6+7+8+9 = 45
-9
978+6+5+4+3+2+1+0=999
it cant
dude its 8
-9
201+69
To create a three-digit addition problem using the digits 1-9 exactly once, choose two three-digit numbers where each digit is unique. For example, you can use 123 and 456. The sum would be 579, which also uses the digits 5, 7, and 9, ensuring that all digits from 1 to 9 are utilized without repetition.
3 addends mean 3 numbers. Regroup I believe means carry over. So I'm thinking something like 36+29+12=
-8
place the digits 1 through 9 into three 3-digit numbers of an addition problem only using 1 through 9 once each
You have to make make 24 with the 3 numbers they gave you. Once you Add, Subtract, Multiply, or Divide, you click the answer of the problem's answer and you Add, Subtract, Multiply, and Divide by the number you have left.
By trial and error, here's one:87 + 93 = 156 + 24