1x38 2x19 So 38 is divisible by 1, 2, 19, 38
124 - 38 /2 = 86/2 = 43
To solve for X in the equation X times -38 equals 114, you need to isolate X by dividing both sides of the equation by -38. This will give you X = 114 / -38, which simplifies to X = -3. Therefore, the value of X that satisfies the equation is -3.
1 x 86, 2 x 43.
38 square = 38 x 38 = 1444.
2 38 = 2 x 19 86 = 2 x 43 hcf = 2
43 - 5 = 38
No
The GCF is 1.
LCD of 38 and 43 is 1
-81 + 43 = -38
the sum of 5 and 38 is 43
43 greater than x - 43+x 43 greater than x plus 35 - 43+x+35 43+35+x=78+x
1 x 38 = 38 2 x 38 = 76 3 x 38 = 114 4 x 38 = 152 5 x 38 = 190 6 x 38 = 228 7 x 38 = 266 8 x 38 = 304 9 x 38 = 342 10 x 38 = 380 11 x 38 = 418 12 x 38 = 456
38 x 43 = 1634 which in Roman numerals is MDCXXXIIII Multiplying XXXXIII (43) by XXXVIII (38) in Roman numerals: XXXXIII*XXXVIII = XXX(XXXX+III)+VIII(XXXX+III) Multiplying out the brackets = MCC+LXXXX+CCCXX+XXIIII Total sum of numerals = MDCXXXIIII (1634) By separating the numerals into tens and units makes multiplication a lot easier. In a way this is what we do today when tackling long multiplication.
It is 38.
38 + 43 = 81