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What is 39x39?

Updated: 4/28/2022
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Chuka Anyanwu

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3y ago

Best Answer

39x39=1,521

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Chuka Anyanwu

Lvl 3
3y ago
This answer is:
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Q: What is 39x39?
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The square root of 1521?

39 39X39=1521


How many 39 x 39 tiles needed to cover 150 sq feet?

150 ft2 is 21600 in2. 39x39 is 1521 in2... Therefore 21600/1521 is 14.20 tiles - or fifteen tiles with some remainder.


What is the 39 squared?

I'm worried that I may not understand your question. If you mean, "What is the numerical answer to 39 squared?" IE., 39^2 or 39x39, you can type it into a calculator or use long multiplication to find out that it is 1521. If you are asking about what 'squared' is: Squaring a number is the same as multiplying it by itself 2 times, so 39^2 = 39 x 39 We can also say that the number 39 is being raised to the power of 2. Cubing a number is multiplying it by itself 3 times (to the power of 3), so 39^3 = 39 x 39 x 39 Note: The little ^ thing indicates that the 2 and 3 coming after it are smaller and written up in the corner.


How many blades of grass on a football field?

First you would have to determine how many were in a smaller area like 1 square foot. This you would have to actually count. Then you would have to figure how many square feet there were to a football field. 150' X 300' equals 45,000 square feet. Multiply the number of blades of grass that you counted in one square foot, times 45,000 and that would tell you approximately how many blades there were. This would be a guess. Or if the field is astroturf then it's easy. Zero. Well there's about 10 blades of grass on a square inch keeping in mind that there's about 39 inches in a meter u do 39x39=15210 per square meter a football field measures about 110 m x 49m... if u take 110x 49= 5390m is the area of a football field u take 5390(area of the football field in meters)x15210(the amount of grass blades in a square meter u get 81,981,900 grass blades on a football field in other words.. 5390x15210= 81, 981,900 blades of grass on a football field per square meter....i only did this because my physics teacher asked us this question n i was online looking for the answer n i found none that were useful n i decided since i found the answer half an hour later to post the answer n the method i used....hope this helps