3a+ax+3b+bx = 3(a+b)+(a+b)x = (a+b)(3+x)
2 x (2a + 3b - 6)
6ab / 3b = 2a so b / b cancels each other out 6 / 3 = 2 / 1 Example: a = 4 and b = 5 6ab = 6 x 4 x 5 = 120 3b = 3 x 5 = 15 120 / 15 = 24 / 3 = 8 = 2a = 2 x 4
-2b + 7 -3b = 2 -2b +7 -3b +2b = 2 + 2b 7 -3b + 3b = 2 + 2b +3b 7-2 = 2-2 + 2b + 3b 5 = 5b 1 = b
a = 3b - c a + c = 3b - c + c a + c = 3b (a + c)/3 = 3b/3 ( a + c ) / 3 = b Do your homework.
2a x 3b = 6ab
54qba
6x - 3b + 8 = 16.Since you cannot simplify the equation, the answer is 6x - 3b = 8.However, if you would like to find x, you can substitute b with '0':6x - 3b + 8 = 166x - 3b = 86x - 3(0) = 86x = 86 6x = 1.33 or 1(1/3)If you want to find b, you can substitute x with '0':6x - 3b + 8 = 166x - 3b = 86(0) - 3b = 8-3b = 8-3 -3b = -2.66 or -2(2/3)
3a+ax+3b+bx = 3(a+b)+(a+b)x = (a+b)(3+x)
The expression 3b x b can be simplified by multiplying the coefficients (numbers) and the variables separately. In this case, 3b x b simplifies to 3b^2, where b^2 represents b squared. This means you multiply the coefficient 3 by the coefficient 1 (since b can be thought of as b^1) to get 3, and you multiply the variable b by itself to get b^2.
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ex: 2x2 + 6bx + 5x + 15b Group 1st 2 terms and last 2 terms. Factor separately. = (2x2 + 6bx) + (5x + 15b) Factor using gcf = 2x(x + 3b) + 5(x + 3b) notice the parenthesis are the same = (2x + 5)(x + 3b)
6b^2 - 3b / 3b 6b^2 - 1 or ( 6b^2 - 3b) / 3b = 2b - 1 Or (6b^2 - 3b ) / 3b = 3b(2b - ) / 3b = 2b - 1
4a + 3b where a and b are your numbers.
2 x (2a + 3b - 6)
6ab / 3b = 2a so b / b cancels each other out 6 / 3 = 2 / 1 Example: a = 4 and b = 5 6ab = 6 x 4 x 5 = 120 3b = 3 x 5 = 15 120 / 15 = 24 / 3 = 8 = 2a = 2 x 4
(x + 3)(a + b)