Starting with an equilateral triangle of side 2, dropping a perpendicular from one vertex to the opposite base creates two equal right angled triangles with hypotenuse of length 2, base length 1 and height of length √(22 - 12) = √3 which is the longer leg of the 30-60-90 triangle. Thus the ratio of longer_leg : hypotenuse is √3 : 2
Base and height
base*height
the base area is = PI * radius^2 = PI*16 the area of the curved surface is = 2*PI*radius*height = 2*PI*4*h ( h - is the height ) = 8*PI*h the ratio base area : curved surface = 134 PI * 16 : 8 * PI *h ( PI*16 )/( 8 * PI * h) = 134 2/h = 134 h = ( 1/67 )//
As area_of_parallelogram = base x height if they are both doubled then: new_area = (2 x base) x (2 x height) = 4 x (base x height) = 4 x area_of_parallelogram Thus, if the base and height of a parallelogram are [both] doubled, the area is quadrupled.
The ratio of the height of an object to the length of its base.
base by height
Assuming that this question should have read, "The perimeter of a rectangle is 38m. The base is four more than two times the height. What is the height?", the answer can be obtained as follows: The perimeter of a rectangle is the twice the sum of its base and height. Call the unknown height h. Then, from the problem statement, 2[h + (2h + 4)] = 38. Expanding and collecting like terms gives 6h = 30 or h = 5 m.
No
It depends on the ratio between the base and the height. Bh=A, and B=(pi)(r2)
Sounds like the triangle is spread out so that (the point is at the top of the rectangle) and (the base of the triangle is the same as the base of the rectangle).Base of rectangle = base of triangleHeight of rectangle = height of triangleWrite the formulas:Area of the rectangle = (base) times (height)Area of triangle = (one half of) (base) times (height)Can you see the ratio now ?
the height of a triangle is three feet longer than the base. The area of the triangle is 35 square feet. Find the height andbase of the triangle
By using the tangent ratio of: opposite/tangent angle = adjacent which is the base
because they have a wide base to height ratio which makes them very stable
Starting with an equilateral triangle of side 2, dropping a perpendicular from one vertex to the opposite base creates two equal right angled triangles with hypotenuse of length 2, base length 1 and height of length √(22 - 12) = √3 which is the longer leg of the 30-60-90 triangle. Thus the ratio of longer_leg : hypotenuse is √3 : 2
There is no ratio of the radius of the base cone to the radius of the base of the cylinder. If they are the same and the height of the cones is the same the ratio of the radius of their bases is 1:1 ant the ratio of the heights is 1:1 and the ratio of the volumes (Vcone:Vcyclinder) is (1/3 π r2 h):(πi r2 h) or 1/3
Suppose the radius of the sphere is R. The base of the cone is the same as the base of the hemisphere so the radius of the base of the cone is also R. The apex of the cone is on the surface of the hemisphere above the centre of the base. That is, it is at the "North pole" position. So the height of the cone is also the radius of the sphere = R. So the ratio is 1.