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Let's denote the two numbers as x and y. We can create a system of equations based on the given conditions: xy = 56 and x + y = 30. To solve this system, we can use substitution or elimination methods. By factoring 56 into its prime factors (2^3 * 7), we can determine that the two numbers are 14 and 4, as they multiply to 56 and add up to 30.
This answer is:
2 and 28
Factor pairs of 56:
1 x 56
2 x 28
4 x 14
7 x 8
28 + 2 = 30
This answer is:
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