45/3 - 2, 45/3 and 45/3 + 2
ie 13, 15 and 17
13,15,17
Divide the sum of the three consecutive odd integers by 3: 45/3 = 15. The smallest of these integers will be two less than 15 and the largest will be two more than 15, so the three consecutive odd integers will be 13, 15, and 17.
To make 92 with consecutive numbers, you can use the formula for the sum of an arithmetic series: n/2 * (first number + last number) = 92. Since we are looking for consecutive numbers, the first number can be 45 and the last number can be 47. Plugging these values into the formula, we get 3/2 * (45 + 47) = 3/2 * 92 = 92, so the consecutive numbers 45, 46, and 47 add up to 92.
Go through each of the numbers, and count how many of them are odd. If you count an odd number of them, then their sum is odd. If you count an even number of them, then their sum is even.
The numbers are 45, 46 and 47.
5*9= 45
13+15+17=45
The numbers are 43 and 45.
The numbers are 43 and 45.
The smallest of the three is 13.
The numbers are 41, 43 and 45.
The numbers are 13, 15 and 17.
The numbers are 45, 47, and 49.
13 + 15 + 17 = 45.
13,15,17
13+15+17=45
If the mean of five consecutive odd numbers is 45, the sum of these numbers is 5 times the mean, which equals 225. The middle number in this set is 45, so the five numbers are 43, 45, 47, 49, and 51. The range is calculated as the difference between the largest and smallest numbers, which is 51 - 43 = 8. Thus, the range of the numbers is 8.