147 / 3 = 49 49 will be the center number, just add and subtract 2 to/from 49 and you get 47+ 49 + 51 = 147
1, 3, 7, 21, 49, 147.
The numbers that multiply to get 147 are its prime factors. To find the prime factors of 147, we start by dividing it by the smallest prime number, which is 3. 147 รท 3 = 49. Then, we divide 49 by 7 (7 is also a prime number), which gives us 7. Therefore, the numbers that multiply to get 147 are 3, 7, and 7.
To determine if 441 is divisible by 3, you can add the digits of 441 together: 4 + 4 + 1 = 9. Since 9 is divisible by 3, then 441 is also divisible by 3. This is because a number is divisible by 3 if the sum of its digits is divisible by 3.
you add up the digits, and if the sum is a multiple of 3, then the number is divisible by 3!
No, 3 is a factor of both. Note that the digits of 120 add up to 3 and those of 147 add up to 12. Both are multiples of 3 so the numbers 120 s and 147 are divisible by 3 and not relatively prime
147 / 3 = 49 49 will be the center number, just add and subtract 2 to/from 49 and you get 47+ 49 + 51 = 147
147 has factors other than 1 and itself, so it is not a prime number. For example, 147 is divisible by 3. (You can quickly check this by adding up the digits of 147: 1 + 4 + 7 = 12. If the sum of the digits is divisible by 3, so is the number.) Therefore, 147 is a composite number.
147 is a composite number. 147/3= 49
No, it is not a prime. 147=3*7*7.
If you can add the integers and they add up to a number divisible by 3, then the number is divisible by 3.
your answer is 3 147 * 3 = 441 21 * 21 = 441
The highest number that goes into both 90 and 147 is 3.
1, 3, 7, 21, 49, 147.
The smallest prime number that divides 147 evenly is three (3).
48
You line up the last numbers and then add it!