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147 / 3 = 49 49 will be the center number, just add and subtract 2 to/from 49 and you get 47+ 49 + 51 = 147
1, 3, 7, 21, 49, 147.
The numbers that multiply to get 147 are its prime factors. To find the prime factors of 147, we start by dividing it by the smallest prime number, which is 3. 147 ÷ 3 = 49. Then, we divide 49 by 7 (7 is also a prime number), which gives us 7. Therefore, the numbers that multiply to get 147 are 3, 7, and 7.
you add up the digits, and if the sum is a multiple of 3, then the number is divisible by 3!
To determine if 441 is divisible by 3, you can add the digits of 441 together: 4 + 4 + 1 = 9. Since 9 is divisible by 3, then 441 is also divisible by 3. This is because a number is divisible by 3 if the sum of its digits is divisible by 3.