The mean of a single number, 26, is 26.
So the question requires 3 numbers that equal 26. When added, multiplied, a combination?
In each case, the number of possibilities is infinite.
Addition:
(0,0,26), (0,1,25), 0,2,24), etc
and then add tenths to the second of the triplet:
(0,0.1,25.9), (0,1.1,24.9), (0,2.1,23.9), etc
and then add 0.2 to the second number, then 0.3, ad so on.
Next add 0.01, 0.02, 0.03 and so on.
And then decimals to 3 digit, 4 digit etc.
Finally start varying the first member - which has been 1 all along.
Multiplication:
Select ANY non-zero number B and let C = 26/B
then 1*B*C = 1*B*26/B = 26
Since the choice of B was arbitrary there are infinitely many such triplets.
Repeat with the first member of the triplet changed to any one of infinitely many non-zero numbers. In each case you will have infinitely many choices for B. All i all, the possibilities are endless.
How about: 1+2+3+20 = 26 out of many other combinations
11
The two numbers that equal 153 are 17 and 9. This is because when you add 17 and 9 together, you get 26, which is the sum of the two numbers. Additionally, when you multiply 17 and 9, you also get 153, making them the two numbers that satisfy the given condition.
whats 2 equal 3
(6 + 4 + 3)*2 = 26
19 + 5 + 2
19 + 5 + 2
3 + 23 = 26 also 7 + 19 = 26 also 13 + 13 = 26
How about: 1+2+3+20 = 26 out of many other combinations
You have to prove it by showing what the mean of the five numbers is. First, you add up the five numbers, which is equal to 15. Then, you divide the sum by 5, which is 3, and not 8.
11
no 3 numbers add to equal 10 and multiply to equal 40.
The two numbers that equal 153 are 17 and 9. This is because when you add 17 and 9 together, you get 26, which is the sum of the two numbers. Additionally, when you multiply 17 and 9, you also get 153, making them the two numbers that satisfy the given condition.
3+26+24= 53
whats 2 equal 3
That means two numbers, which when added together equal 5, e.g. 2 + 3 = 5
It is simply: 3+23 = 26 because 3 and 23 are prime numbers