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The mean of a single number, 26, is 26.

So the question requires 3 numbers that equal 26. When added, multiplied, a combination?

In each case, the number of possibilities is infinite.

Addition:

(0,0,26), (0,1,25), 0,2,24), etc

and then add tenths to the second of the triplet:

(0,0.1,25.9), (0,1.1,24.9), (0,2.1,23.9), etc

and then add 0.2 to the second number, then 0.3, ad so on.

Next add 0.01, 0.02, 0.03 and so on.

And then decimals to 3 digit, 4 digit etc.

Finally start varying the first member - which has been 1 all along.

Multiplication:

Select ANY non-zero number B and let C = 26/B

then 1*B*C = 1*B*26/B = 26

Since the choice of B was arbitrary there are infinitely many such triplets.

Repeat with the first member of the triplet changed to any one of infinitely many non-zero numbers. In each case you will have infinitely many choices for B. All i all, the possibilities are endless.

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Q: What 3 numbers equal the mean of 26?
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