221
11 and 18
11 and 16.
11 is a tricky one, but this is how:if the sum of every other digit minus the sum of all the other digits equals a multiple of 11example:Q: Is 164725 divisible by 11?A: Yes. and this is why... first you take every other digit 164725, then add them 6+7+5=18. Now take the rest of the numbers 164725 and add them, 1+4+2=7. After that subtract them, 18-7=11, and 11 is a multiple of 11 (11x1=11).
21
You can select 12 numbers for the first digit, 11 numbers for the second digit, and 10 numbers for the third digit; so 12*11*10 = 1320 sets of 3 numbers can be made out of 12 different numbers.
14
99990 Note that if you add 11 to my answer you get a 6-digit number therefore it must be the largest 5-digit whole multiple of 11.
221
Eleven digit numbers are those in the range between 9,999,999,999 and 100,000,000,000 exclusive. There are 90,000,000,000 of these.
11
11
There are more 12-digit palindromic numbers than 11-digit palindromic numbers. This is because the number of possible 12-digit palindromic numbers is greater than the number of possible 11-digit palindromic numbers. In general, the number of palindromic numbers of length n is 9 * 10^((n-1)/2), so for 11-digit palindromic numbers, there are 9 * 10^5 = 900,000 possibilities, while for 12-digit palindromic numbers, there are 9 * 10^6 = 9,000,000 possibilities.
Hint, but not your answer: You know your answer has to be between 11 and 99. Furthermore, it has to be a square. One, two, and three when squared are still single digit numbers. Four squared is 16, which is not squaring the ones digit. Keep going...
11 and 18
11 and 13.
21