To find six numbers with a range of 2 and a median of 4, we can start by placing the median 4 in the middle. Since the range is 2, the numbers on either side of the median will be 2 and 6. This leaves us with the numbers 2, 4, 4, 4, 6, and 6. These six numbers have a range of 2 and a median of 4.
take the 2 middle numbers, add them together, then divide by 2 and that number is your median.
To find the median of a set of numbers write them in order, then: * if there are an odd number of numbers then the median is the number in the middle * otherwise there are an even number of numbers and the median is the mean average of the two numbers in the middle. With 4 numbers there is an even number of numbers, so the median is the mean average of the 2nd and 3rd numbers when they are sorted into order. Example: Find median of {3, 9, 4, 5} Ordered → {3, 4, 5, 9} → median = mean_average(4, 5) = (4 + 5) ÷ 2 = 4.5
To find the four numbers with a range of 6, a mean of 4, and a median of 3, we can start by setting up the median as the second and third numbers in ascending order. Since the median is 3, the second and third numbers are both 3. With a mean of 4, the sum of all four numbers is 4 * 4 = 16. To have a range of 6, the smallest number must be 3 - 3 = 0 and the largest number must be 3 + 6 = 9. Therefore, the four numbers are 0, 3, 3, and 9.
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The median is the middle value when a set of numbers is arranged in ascending or descending order. In this case, the numbers 4 and 8 are already in ascending order. Since there are only two numbers, the median is the average of the two middle numbers, which is (4 + 8) / 2 = 6.
2 4 4 6 8
Well, darling, if you want a range of 7 with a median of 5, you'll need a set of numbers that are evenly spaced. So, let's go with 2, 5, 8, and 11. That way, you've got a range of 7 and a sassy median of 5.
Mean = 4 Median = 3Mode = 2 and 3Range = 6Mean = 4 Median = 3Mode = 2 and 3Range = 6Mean = 4 Median = 3Mode = 2 and 3Range = 6Mean = 4 Median = 3Mode = 2 and 3Range = 6
To find four numbers with a range of 6, a mean of 4, and a median of 3, we can start by setting up an equation for the mean. The mean is the sum of all numbers divided by the total number of values. So, 4 = (a + b + c + d) / 4, where a, b, c, and d are the numbers. Since the median is 3, the two middle numbers must be 3 and 3. The range is the difference between the maximum and minimum values, so the numbers could be 0, 3, 3, and 6.
take the 2 middle numbers, add them together, then divide by 2 and that number is your median.
To find the median of a set of numbers write them in order, then: * if there are an odd number of numbers then the median is the number in the middle * otherwise there are an even number of numbers and the median is the mean average of the two numbers in the middle. With 4 numbers there is an even number of numbers, so the median is the mean average of the 2nd and 3rd numbers when they are sorted into order. Example: Find median of {3, 9, 4, 5} Ordered → {3, 4, 5, 9} → median = mean_average(4, 5) = (4 + 5) ÷ 2 = 4.5
Mean: 11 Median: 11 Mode: 4 Range: 18
1, 4, 10
If its a odd set of numbers then the median will be (n+1/2)th term. where, n=set of numbers like 2,4,5 then the median will be (3+1/2)th term=2nd term=4. therefore the median is 4 And if its a even set of numbers like 1,4,7,9,6,8 then the median will be the (sum of mid numbers/2) 7+9/2=8 therefore the median is 8
To find the four numbers with a range of 6, a mean of 4, and a median of 3, we can start by setting up the median as the second and third numbers in ascending order. Since the median is 3, the second and third numbers are both 3. With a mean of 4, the sum of all four numbers is 4 * 4 = 16. To have a range of 6, the smallest number must be 3 - 3 = 0 and the largest number must be 3 + 6 = 9. Therefore, the four numbers are 0, 3, 3, and 9.
Assuming that you want to discount luck (if not, the answer would be 1), and that the guesser always guesses the median of the remaining range, the answer would be the (ceiling of the log(base 2) of the count of numbers in the range). If the log(base 2) is an exact integer, add 1. Example 1, pick a number between 1 and 9. There are 9 numbers in the range, so the log(base2) of 9 is ~3.16. The ceiling of that is 4. Do not add 1 for a final answer of 4. The full range is 1,2,3,4,5,6,7,8,9. The median is 5 First guess is 5. Higher - 6,7,8,9 is remaining range. 7 and 8 are the median numbers Second Guess is 8. Lower - 6,7 is the remaining range. 6 and 7 are the median numbers. Third guess is 7. Lower - 6 is the remaining range. 6 is the median number Fourth guess is 6. Correct. Example 2, pick a number between 1 and 16. There are 16 numbers in the range, so the log(base 2) of 16 is 4. The ceiling of 4 is 4. Add the 1 because the Log(base 2) is an integer, for a final answer of 5. Full range is 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16. The median numbers are 8 and 9. First Guess is 9. Lower - 1,2,3,4,5,6,7,8 is the remaining range. 4 and 5 are the median numbers Second Guess is 4. Higher - 5,6,7,8 is the remaining range. 6 and 7 are the median numbers. Third Guess is 6. Higher - 7,8 is the remaining range. 7 and 8 are the median numbers. Fourth Guess is 7. Higher - 8 is the remaining range. 8 is the median. Fifth guess is 8. Correct Both of these examples show worst case scenarios. A "lucky guess" will reduce the number of guess needed, possibly all the way to 1. Note: I do realize that to a math purist, in the examples where I said that the median numbers were x and y, the correct answer is that the median number is between x and y. Since I can not guess the number between the two numbers, I am bending the definition of median to treat the two bordering numbers as the median when the strict definition would list the median as being between those two numbers.
can start by finding the minimum and maximum values. Since the range is 8, the minimum value must be 6 - (8/2) = 2 and the maximum value must be 6 + (8/2) = 10. Now we need to find 5 numbers between 2 and 10 that have a median of 6. Since there are an odd number of values, the median will be the middle value when the numbers are sorted in ascending order. Therefore, we can choose any two numbers less than 6 and two numbers greater than 6, and then include 6 as the middle value. For example, we could choose the following five numbers: 2, 4, 6, 8, 10. The range of these numbers is indeed 8, and their median is also 6. Therefore, one possible set of five numbers with a range of 8 and a median of 6 is 2, 4, 6, 8, and 10.