3 or 7 - depending on whether you count a transposed array as different. 1*64 2*32 4*16 8*8
You can solve this problem by doing the equation for combinations: which in this case is 4x3x2x1. So the answer is 12 different ways. no actually the answer is 24 different ways because 4x3x2x1=24 same as 4!
You can show 24 cans in one row, 12 cans in 2 rows, 8 cans in 3 rows, and 6 cans in 4 rows.
I think 4 different ways
There are eight possible combinations... 1 row of 24 cans 2 rows of 12 cans 3 rows 8 cans 4 rows of 6 cans 6 rows of 4 cans 8 rows of 3 cans 12 rows of 2 cans 24 rows of 1 can
3 or 7 - depending on whether you count a transposed array as different. 1*64 2*32 4*16 8*8
There are 11880 ways.
You can solve this problem by doing the equation for combinations: which in this case is 4x3x2x1. So the answer is 12 different ways. no actually the answer is 24 different ways because 4x3x2x1=24 same as 4!
You can find 12% of 400 two different ways:1. 1% of 400 is 4. So, 12% of 400, or 4*12, is 48.2. 12% of 100 is 12. So, 12% of 400, or 4*12, is 48.
4+4=8
You can show 24 cans in one row, 12 cans in 2 rows, 8 cans in 3 rows, and 6 cans in 4 rows.
2/12 4/24 6/36 8/48
There are an infinite amount of ways. Eg: 3/4=6/8=9/12=12/16=15/20=18/24
4 (or eight if you count transposed arrays as being different).
Oh honey, there are so many arrays for 12, it's like trying to count all the wrinkles on my face! Let's see, you've got 1 x 12, 2 x 6, and 3 x 4. But hey, if you want to get fancy, you can also do 4 x 3, 6 x 2, and 12 x 1. Math can be a real party sometimes!
I think 4 different ways
There are many ways, but 5 different ways are: 3/1, 6/2, 9/3, 12/4, and 15/5.