3x4,1x12 and 6x2
3 or 7 - depending on whether you count a transposed array as different. 1*64 2*32 4*16 8*8
You can solve this problem by doing the equation for combinations: which in this case is 4x3x2x1. So the answer is 12 different ways. no actually the answer is 24 different ways because 4x3x2x1=24 same as 4!
You can show 24 cans in one row, 12 cans in 2 rows, 8 cans in 3 rows, and 6 cans in 4 rows.
I think 4 different ways
There are eight possible combinations... 1 row of 24 cans 2 rows of 12 cans 3 rows 8 cans 4 rows of 6 cans 6 rows of 4 cans 8 rows of 3 cans 12 rows of 2 cans 24 rows of 1 can
3 or 7 - depending on whether you count a transposed array as different. 1*64 2*32 4*16 8*8
There are 11880 ways.
You can solve this problem by doing the equation for combinations: which in this case is 4x3x2x1. So the answer is 12 different ways. no actually the answer is 24 different ways because 4x3x2x1=24 same as 4!
You can find 12% of 400 two different ways:1. 1% of 400 is 4. So, 12% of 400, or 4*12, is 48.2. 12% of 100 is 12. So, 12% of 400, or 4*12, is 48.
You can show 24 cans in one row, 12 cans in 2 rows, 8 cans in 3 rows, and 6 cans in 4 rows.
4+4=8
2/12 4/24 6/36 8/48
There are an infinite amount of ways. Eg: 3/4=6/8=9/12=12/16=15/20=18/24
4 (or eight if you count transposed arrays as being different).
I think 4 different ways
There are many ways, but 5 different ways are: 3/1, 6/2, 9/3, 12/4, and 15/5.
1 x 24 2 x 12 3 x 8 4 x 6