3 or 7 - depending on whether you count a transposed array as different. 1*64 2*32 4*16 8*8
You can solve this problem by doing the equation for combinations: which in this case is 4x3x2x1. So the answer is 12 different ways. no actually the answer is 24 different ways because 4x3x2x1=24 same as 4!
You can show 24 cans in one row, 12 cans in 2 rows, 8 cans in 3 rows, and 6 cans in 4 rows.
I think 4 different ways
There are eight possible combinations... 1 row of 24 cans 2 rows of 12 cans 3 rows 8 cans 4 rows of 6 cans 6 rows of 4 cans 8 rows of 3 cans 12 rows of 2 cans 24 rows of 1 can
3 or 7 - depending on whether you count a transposed array as different. 1*64 2*32 4*16 8*8
4 (or eight if you count transposed arrays as being different).
There are 11880 ways.
You can solve this problem by doing the equation for combinations: which in this case is 4x3x2x1. So the answer is 12 different ways. no actually the answer is 24 different ways because 4x3x2x1=24 same as 4!
You can find 12% of 400 two different ways:1. 1% of 400 is 4. So, 12% of 400, or 4*12, is 48.2. 12% of 100 is 12. So, 12% of 400, or 4*12, is 48.
4+4=8
You can show 24 cans in one row, 12 cans in 2 rows, 8 cans in 3 rows, and 6 cans in 4 rows.
2/12 4/24 6/36 8/48
There are an infinite amount of ways. Eg: 3/4=6/8=9/12=12/16=15/20=18/24
Oh honey, there are so many arrays for 12, it's like trying to count all the wrinkles on my face! Let's see, you've got 1 x 12, 2 x 6, and 3 x 4. But hey, if you want to get fancy, you can also do 4 x 3, 6 x 2, and 12 x 1. Math can be a real party sometimes!
I think 4 different ways
1 x 24 2 x 12 3 x 8 4 x 6