22*5*13 = 260
The prime factorization of 260 in exponential form is written as: 22 x 5 x 13
√260 . . 260 can be factored as 4 x 65, so we can now put :- √260 = √(4 x 65) = √(2² x 65) = 2√65. Note that 65 is the product of two prime numbers (5 x 13) so the expression cannot be further simplified.
260 + ((0 +42 + 45)/3) = 260 + 87/3 = 260 + 29 = 289
5*2*2*13
The prime numbers between 230 and 260 are 233, 239, 241, 251, and 257.
They are: 233239241251257
233 239 241 251 257.
233 239 241 251 257.
211 223 227 229 233 239 241 251 257.
260 is a composite, like all even numbers greater than 2.260 is composite.
Composite numbers are integers greater than 1 that are not prime, meaning they have factors other than 1 and themselves. Between 250 and 260, the composite numbers are 252, 254, 255, 256, 258, and 259. These numbers can be divided evenly by numbers other than 1 and themselves, making them composite.
262
No, prime numbers must have exactly two divisors which result in an integer dividend; these numbers are one (1) and the number itself. Since 260 is an even number it has two (2) as a such a divisor. Thus, it has more than two and is not prime.
230 or 260
Prime numbers only 1 and itself can go in to it composite 1 itself and other factors therefore 260 is a composite number
260 is a composite number, like all numbers greater than 1 that end in 0.