The multiples of 2 are numbers that can be divided evenly by 2. In this case, the multiples of 2 up to 100 are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100.
Multiples of 2 are numbers that are divisible by 2. In the range from 1 to 100, the multiples of 2 are 2, 4, 6, 8, 10, and so on up to 100. This sequence forms an arithmetic progression with a common difference of 2. The formula to find the nth multiple of 2 is 2n.
the multiples of 2 are 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,100
Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72
ALL even numbers are multiples of 2... so if there is an uneven multiples of six than they aren't multiple of two.
Yes. In fact all even numbers (not just 4) will share their multiples with 2.
2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,100
' 1 ' is a factor of every whole number . . . . . 100 of them' 2 ' is a factor of every even number . . . . . 50 of them' 3 ' has 33 multiples up to 100 . . . . . 33 of them' 4 ' has 25 multiples up to 100 . . . . . 25 of them' 5 ' has 20 multiples up to 100 . . . . . 20 of them' 6 ' has 16 multiples up to 100 . . . . . 16 of them' 7 ' has 14 multiples up to 100 . . . . . 14 of them' 8 ' has 12 multiples up to 100 . . . . . 12 of them' 9 ' has 11 multiples up to 100 . . . . . 11 of themTotal . . . . . . . . . . . . . . . . . . . . . . . . . 281 one-digit factors in all whole numbers 1 to 100 .
Multiples of 2 are numbers that are divisible by 2. In the range from 1 to 100, the multiples of 2 are 2, 4, 6, 8, 10, and so on up to 100. This sequence forms an arithmetic progression with a common difference of 2. The formula to find the nth multiple of 2 is 2n.
There are an infinite number of multiples of 100. 100, 200, 300,400, ....
10 is two in multiples of 2 to 100
the multiples of 2 are 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,100
There are several multiples of 100. The multiples of 1 are: 1, 2, 3, 4, 5, 6, 7, 8 ect. All you have to do is add 2 zeroes. The multiples of 100 are: 100, 200, 300, 400, 500, 600, 700, 800 ect.
30, 60, 90
They have to be multiples of 15 so all of them will be multiples of 3. They all have to be even so you are left with 30, 60, 90
1.draw up a chart 1-100 2.get rid of 2's multiples 3.get rid of 3's multiples 4.get rid of 5's multiples 5.get rid of 7's multiples 6. all the left over numbers are prime.
All multiples of 8 are also multiples of 2, but not all multiples of 2 are multiples of 8.
Common multiples of 100 and 2 include any multiple of 100.