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the way I see it is, if you have 4 consecutive numbers, the sum of the highest and lowest will be the same as the sum of the 2 middle ones, eg: 10,11,12,13, 10+13=23, 11+12=23. so if you divide 74 by 2, then that number by 2, if you just fan them out youll get the answer: 74/2=37, 37/2=18.5, alright doesnt exactly work, just use 18 and 19 as the middle ones and the answer is: 17, 18, 19, 20

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Q: What are four consecutive numbers that add up to 74?
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What are four consecutive numbers that add up to 75?

17+18+19+20=74, mulitply does not come close... what is the actuial question?


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Three consecutive integers are such thatwhen they are taken in increasing order and multiplied by 23 and 4 respectivelythey add up to 74 find these numbers?

They are seven, eight, and nine. Hint, letting m be the middle number, 9m will be close to 74. Further hint, 2(m - 1) + 3m + 4(m + 1) = 2m - 2 + 3m + 4m + 4 = 9m + 2. Thus, the middle integer must be 8. Three consecutive integers are such thatwhen they are taken in increasing order and multiplied by 23 and 4 respectivelythey add up to 74 find these numbers?


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In order to do any consecutive integer problem, you should think of the numbers as x's. Here's what I did to solve this problem (and what you can do to solve future problems): (x) + (x +1) + (x +2) + (x + 3) = 290 4x + 6 = 290 4x = 284 x = 71, therefore the four numbers are 71, 72 (71 + 1), 73 (71 + 2), and 74 (71 + 3).


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