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the way I see it is, if you have 4 consecutive numbers, the sum of the highest and lowest will be the same as the sum of the 2 middle ones, eg: 10,11,12,13, 10+13=23, 11+12=23. so if you divide 74 by 2, then that number by 2, if you just fan them out youll get the answer: 74/2=37, 37/2=18.5, alright doesnt exactly work, just use 18 and 19 as the middle ones and the answer is: 17, 18, 19, 20
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Find two consecutive odd numbers such that the sum of their squares is 74?
5 and 7 52+72 = 74
Three consecutive integers are such thatwhen they are taken in increasing order and multiplied by 23 and 4 respectivelythey add up to 74 find these numbers?
They are seven, eight, and nine. Hint, letting m be the middle number, 9m will be close to 74. Further hint, 2(m - 1) + 3m + 4(m + 1) = 2m - 2 + 3m + 4m + 4 = 9m + 2. Thus, the middle integer must be 8. Three consecutive integers are such thatwhen they are taken in increasing order and multiplied by 23 and 4 respectivelythey add up to 74 find these numbers?
What are four consecutive numbers that add up to 75?
Well, honey, if you put on your thinking cap, you'll see that 18 + 19 + 20 + 21 adds up to 78, not 75. So, you might want to try again with those numbers. Math can be a tricky little devil sometimes, but I have faith in you!
Four consecutive integers whose sum is 290?
In order to do any consecutive integer problem, you should think of the numbers as x's. Here's what I did to solve this problem (and what you can do to solve future problems): (x) + (x +1) + (x +2) + (x + 3) = 290 4x + 6 = 290 4x = 284 x = 71, therefore the four numbers are 71, 72 (71 + 1), 73 (71 + 2), and 74 (71 + 3).
What four consecutive even numbers add to 300?
72+74+76+78 =300. Explanation: let x be the first number. Then the others are x+2,x+4 and x +6. x +( x + 2) +( x + 4) + (x + 6 ) = 300 4x + 12 = 300. 4x = 288 x = 288/4 = 72. So, the numbers are 72,74,76 and 78.
