Multiples of 3: 69 72 75 78 81 84 87 90 93 96 99 102 105 108 111
Multiples of 6: 72 78 84 90 96 102 108
Multiples of 8: 72 80 88 96 104 112
72 and 96
It is: 90
Assuming you want a number that is a multiple of all of 4, 6, 9: It is a multiple of their lowest common multiple. lcm(4, 6, 9) = 36 So you require a multiple of 36 between 67 and 113: 67 ÷ 36 = 1 r 31 → 1st multiple of 36 > 67 is 2 x 36 = 72 113 ÷ 36= 3 r 5 → last multiple of 36 < 113 is 3 x 36 = 108 → both 78 and 108 are numbers between 67 and 113 which are multiples of all of 4, 6 & 9. If not, re-ask being more specific in your requirements.
There are 67.
72, 108
84
72 and 108.
It is: 90
Just 84
Just one: 84.
To find the numbers Lena could choose between 67 and 113 that are multiples of 3, 6, and 7, we first determine the least common multiple (LCM) of these numbers. The LCM of 3, 6, and 7 is 42. Now, we identify the multiples of 42 within the range: 84 and 126. Since 126 exceeds 113, the only number Lena could choose is 84.
Assuming you want a number that is a multiple of all of 4, 6, 9: It is a multiple of their lowest common multiple. lcm(4, 6, 9) = 36 So you require a multiple of 36 between 67 and 113: 67 ÷ 36 = 1 r 31 → 1st multiple of 36 > 67 is 2 x 36 = 72 113 ÷ 36= 3 r 5 → last multiple of 36 < 113 is 3 x 36 = 108 → both 78 and 108 are numbers between 67 and 113 which are multiples of all of 4, 6 & 9. If not, re-ask being more specific in your requirements.
* 72 * 90 * 108 All multiples of 18 are multiples of 9 and of 6, because 9 x 2 = 18, and 6 x 3 = 18. So you only have to find multiples of 18 that occur between 67 and 113. 3x18=54, no good! 4x18=72. YES 5x18=90. YES 6x18=108. YES 7x18=126, no good.
There are 67.
90
It is: 90
84.
It is: 90