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Prime factors of 42 are: 2, 3 and 7

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Q: What are the 3 digit prime numbers of 42?
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Related questions

What is the largest 3 digit prime numbers?

997 is the largest 3-digit prime number.


What are all of the one-digit prime numbers?

2, 3, 5, and 7 are the only one-digit prime numbers.


What is the prime factorization for -42?

The prime factors of 42 are 2, 3, and 7. These prime numbers multiplied create 42.2*3*7 = 422 x 3 x 7 = 42.


What two digit numbers have the most factors in their prime factorization?

One way to solve this is to multiply the lowest prime numbers together, starting from 2: 2x3=6. 6x5=30. Multiplying by 7 would yield a 3-digit number, so we are looking for all 2-digit numbers with 3 distinct prime factors. We already have 30. 2x3x7=42. 2x3x11=66. 2x3x13=78. 2x5x7=70. So, to answer the original question, the 2-digit numbers that have the most factors in their prime factorization are, in ascending order, 30, 42, 66, 70, and 78.


What one-digit number is the product of two consecutive prime numbers?

There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)


Prime Factor numbers of 42?

1, 2, 3, 7 are the prime factors of 42.


What are the steps for finding the prime numbers of 42?

The prime factors of 42 are 2, 3 and 7


What is a prime factorization of -42?

The prime factors of 42 are 2, 3 and 7.


What is 42 as a product of prime factors?

42 = 2 * 3 * 7the prime factors of 42 are 1,2,3,7the product of these numbers is... 1x2x3x7 = 42


What are the prime numbers for 42?

7, 3, 2


Write 42 as a product of its prime numbers?

It is: 2*3*7 = 42


What is 42 of prime numbers?

2 x 3 x 7 = 42