Q: What are the factor pairs 28?

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1 & 28, 2 & 14, 4 & 7

(28,1)(14,2)(7,4)

The factor pairs of 56 are: 1 × 56 2 × 28 4 × 14 7 × 8

its a factor with two pairs of the same number

12 has 3 factor pairs and the pairs are (1,12), (2,6) and (3,4).

Related questions

The factor pairs of 28 are 1*28, 2*14, and 4*7

There are 3 factor pairs of 28. 28 = 1 x 28 28 = 2 x 14 28 = 4 x 7

28 has three factor pairs which are:28 = 1 x 2828 = 2 x 1428 = 4 x 7

28,114,27,4

1 and 28 2 and 14 4 and 7

1 & 28, 2 & 14, 4 & 7

1,282,144,7-1,-28-2,-14-4,-7

1, 28 2, 14 4, 7

The factor pairs of 112 are 1*112, 2*56, 4*28, 7*16, and 8*14

The factor pairs of 56 are: 1, 56; 2, 28; 4, 14; 7, 8 Therefore, if you exclude itself and 1, there are three factor pairs, but if you include itself and 1, there are four factor pairs.

The factor pairs of 56 are 1 x 56, 2 x 28, 4 x 14, and 7 x 8.

1 and 28, 2 and 14, 4 and 7.