The factors of 5 are 1 and 5. The factors of 2 are 1 and 2.
25 factors to [5 5] 125 factors to [5 5 5] 200 factors to [2 2 2 5 5] Common factors are [5 5] so GCF = 25 25
The factors of 10 are: 1, 2, 5, and 10.The prime factors of 10 are: 2 and 5.The factors of 15 are: 1, 3, 5, and 15.The prime factors of 15 are: 3 and 5.
The prime factors of 200 are 2 and 5 or as a product of its prime factors 2*2*2*5*5 = 200
Do you mean, what is it evenly divisible by? You can answer questions like these by finding the factors of the number and multiplying different factors: 215 ends in 5, so we know 5 is one if its factors. Divide by 5: we're left with 43. 43 is a prime number, it can't be factored any more. 215 is only divisible by 5 and 43. As a better example of how this technique works, consider 100. 100's factors are 5, 5, 2, and 2. By multiplying together different factors, we can discover that 100 is not only divisible directly by its factors 5 and 2, but also by 5*5, 2*2, 5*2, 5*5*2 and 2*2*5.
Factors: (will fill in later).Prime Factors: 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 5, 5, 5, 5, 5, 5, 5, 5, 5
The factors of 5 are 1 and 5. The factors of 2 are 1 and 2.
25 factors to [5 5] 125 factors to [5 5 5] 200 factors to [2 2 2 5 5] Common factors are [5 5] so GCF = 25 25
The prime factors are: 2 x 2 x 5
They have the prime factors 2 and 5 in common.
The prime factors of 10 are: 2 and 5.
The factors of 20 are: 1, 2, 4, 5, 10, and 20.The prime factors of 20 are: 2 and 5.The factors of 50 are: 1, 2, 5, 10, 25, and 50.The prime factors of 50 are: 2 and 5.
The prime factors for 20 are: 2 . 2 . 5 . 5
The prime factors of 260 are 2, 2, 5, and 13.Its prime factors are: 2, 5 and 13
The prime factors of 2, 3 and 5 are 2, 3 and 5 respectively.
The factors of 8 are 1, 2, 4, and 8. The prime factors are 2, 2, and 2. The factors of 10 are 1, 2, 5, and 10. The prime factors are 2 and 5.
The prime factors of 200 are 2 and 5 As a product of its prime factors: 2*2*2*5*5 = 200