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1, 3, 5, 7, 9, 11

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Q: What are the first six positive odd numbers?

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The sum of the first six positive numbers (1 to 6) is 21.

There are 5760 such numbers.

There have to be an even number of odd numbers in each group, and each group must have more than two odd numbers (since 19 + 17 is only 36); thus there must be four in one group and six in the other. There are many ways to get four odd numbers to add up to to 50; for example, you could take 1, 13, 17 and 19. The remaining six odd numbers will then also add up to 50.

Let the first odd number be 2n-5 (n ≥ 3), then the 6 consecutive odd numbers are: 2n-5, 2n-3, 2n-1, 2n+1, 2n+3, 2n+5 And their sum is: 2n-5 + 2n-3 + 2n-1 + 2n+1 + 2n+3 + 2n+5 = 12n The greatest common factor for all n(≥ 3) of 12n is 12. Thus 12 is the greatest whole number that MUST be a factor of the sum of any six consecutive positive odd numbers.

Fifty-four divided by six is equal to positive nine because fifty-four and six are both positive numbers.

Related questions

The sum of the first six positive numbers (1 to 6) is 21.

2

999999 is six digits and odd.

1 , 3 , 5 , 7 , 9 , 11 .

It is -999999.The smallest POSITIVE odd number is 100001.

It is -999999.The smallest POSITIVE odd number is 100001.

yes 100

The 3 consecutive odd positive integers are 7, 9 and 11.

1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36

5+5+5+5+1 That is only 5 numbers being added. There can be no answer for six numbers for the following reasons: The numbers are all odd. Two odd numbers make an even number. Two even numbers make an even number. 21 is odd. Take 6 odd numbers and add them up in pairs. Each pair of odd numbers gives an even number so there are 3 even numbers. Even + Even + Even = Even. So sum of any six odd numbers is even but 21 is not even.

Even. All numbers ending in six are even.

Impossible.