A right triangle with a hypotenuse of 40 inches and a side of 8 inches has a leg length of 39.19 inches so the shorter leg IS 8 inches.
the answer is 8
If 8 is a leg and 12 is the hypotenuse, the other leg is: 8.944
There are an infinite number of different right triangles, all with different leg lengths, that all have hypotenuses of 21. None of the pairs is integral. A few of them have leg lengths of: 1, sqrt(440) 2, sqrt(437) 3, sqrt(432) 4, sqrt(425) 5, sqrt(416) 6, sqrt(405) sqrt(41), 20 7, sqrt(392) 8, sqrt(377) 9, sqrt(360) 10, sqrt(341)
Using Pythagoras' theorem the hypotenuse works out as 10 cm
The length of the hypotenuse of a right triangle with legs of lengths 6 and 8 is: 10
In a right triangle with a hypotenuse of 11 and one leg of 8, the other leg is: 7.55
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
The length of the hypotenuse of a right triangle with legs of lengths 6 and 8 inches is: 10 inches.
hypotenuse= 16.24
17
A right triangle with a hypotenuse of 40 inches and a side of 8 inches has a leg length of 39.19 inches so the shorter leg IS 8 inches.
The hypotenuse is 10 yards long.
The hypotenuse is the square root of (82 +152) = 17.
10 units in length
The hypotenuse of a 30-60-90 triangle whose long leg is 13 centimeters is: 15.01 cm
if one leg is 10-2=8 then Pythagoras tells us 10^2 = 8^2 + leg^2 so second leg squared = 100-64 = 36 so legs are 6 and 8 inches