It is 80.
Assuming you want a number that is a multiple of all of 4, 6, 9: It is a multiple of their lowest common multiple. lcm(4, 6, 9) = 36 So you require a multiple of 36 between 67 and 113: 67 ÷ 36 = 1 r 31 → 1st multiple of 36 > 67 is 2 x 36 = 72 113 ÷ 36= 3 r 5 → last multiple of 36 < 113 is 3 x 36 = 108 → both 78 and 108 are numbers between 67 and 113 which are multiples of all of 4, 6 & 9. If not, re-ask being more specific in your requirements.
80 and 100
72, 90, 108
All the multiples of 4 are also multiples of 2.
The numbers between 67 and 113 that are multiples of 2, 4, and 5 are 80 and 100.
It is 80.
80 and 100
No, 16 is not between 67 and 113. Multiples of 8 in that range include, 72, 80, 88, 96, 104 and 112.
* 72 * 90 * 108 All multiples of 18 are multiples of 9 and of 6, because 9 x 2 = 18, and 6 x 3 = 18. So you only have to find multiples of 18 that occur between 67 and 113. 3x18=54, no good! 4x18=72. YES 5x18=90. YES 6x18=108. YES 7x18=126, no good.
Assuming you want a number that is a multiple of all of 4, 6, 9: It is a multiple of their lowest common multiple. lcm(4, 6, 9) = 36 So you require a multiple of 36 between 67 and 113: 67 ÷ 36 = 1 r 31 → 1st multiple of 36 > 67 is 2 x 36 = 72 113 ÷ 36= 3 r 5 → last multiple of 36 < 113 is 3 x 36 = 108 → both 78 and 108 are numbers between 67 and 113 which are multiples of all of 4, 6 & 9. If not, re-ask being more specific in your requirements.
80 and 100
72, 90, 108
A multiple of 356 would be a number than 356 can divide into. So there is no number between 67 and 113 that can be divided by 356. The number 89 is between is between 67 and 113 and it can be divided into 356 evenly, so it is a factor, but not a multiple. 356 is a multiple of 89.
Just multiply 67 by different integers, in this case: 67 x 1 67 x 2 etc.
There is 67
The prime numbers from 2 to 113 are listed below... 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113