The LCM of 3, 4, 6, and 8 is 24 The multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, and so on. The multiples of 4 are 4, 8, 12, 16, 20, 24, and so on. The multiples of 6 are 6, 12, 18, 24, and so on. The multiples of 8 are 8, 16, 24, and so on. So the LCM of 3, 4, 6, and 8 is 24.
Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72
All numbers that are multiples of 360 are multiples of 6, 8 and 10.
Multiples of 1- 1, 2 3, 4 ,5, 6, 7, 8, 9, 10-- Like counting Multiples of 2- 2,4,6,8,10,12, ect. Multiples of 3- 3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54, Multiples of 4- Multiples of 5- Multiples of 6
Do you mean 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12? Do you want multiples of each one separately? e.g. multiples of 2, multiples of 3, multiples of 4? The answers to the times tables will do it if that is what you want. eg 2, 4, 6, 8, 10... 3, 6, 9, 12, 15... 4, 8, 12, 16, 20... etc.
What are three common multiples of 2 6 8
The LCM of 3, 4, 6, and 8 is 24 The multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, and so on. The multiples of 4 are 4, 8, 12, 16, 20, 24, and so on. The multiples of 6 are 6, 12, 18, 24, and so on. The multiples of 8 are 8, 16, 24, and so on. So the LCM of 3, 4, 6, and 8 is 24.
No multiples of 24 are factors of 6.1, 2, 3, 4 and 8 are factors of 24 that are not multiples of 6.
Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72
4 and 8 are multiples of 2. 6 and 9 are multiples of 3. 40 and 50 are multiples of 10.
All numbers that are multiples of 360 are multiples of 6, 8 and 10.
Multiples of 1- 1, 2 3, 4 ,5, 6, 7, 8, 9, 10-- Like counting Multiples of 2- 2,4,6,8,10,12, ect. Multiples of 3- 3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54, Multiples of 4- Multiples of 5- Multiples of 6
Factors that are multiples of 3 and factors of 24? factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24. only 3, 6, 12, and 24 are multiples of 3.
4=8,12,16 6=12,18,24 8=16,40,48
The multiples of 10 are: 1, 2, 5, 10 The multiples of 5 are: 1 and 5. The multiples of 6 are: 1, 2, 3, and 6. The multiples of 8 are: 1, 2, 4, and 8. The number that they all have in common is 1, so the lcd is one.
Oh, dude, like, totally! If a number is a multiple of 6, it means it can be divided evenly by 6, right? And since 6 is just 3 times 2, any number that's a multiple of 6 is also a multiple of 3. It's like getting two for the price of one, man.
Do you mean 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12? Do you want multiples of each one separately? e.g. multiples of 2, multiples of 3, multiples of 4? The answers to the times tables will do it if that is what you want. eg 2, 4, 6, 8, 10... 3, 6, 9, 12, 15... 4, 8, 12, 16, 20... etc.