FALSE
2, 4, 6, 8 or 0
Oh, dude, multiples of 2 between 0 and 20? Like, that's easy peasy. You've got 2, 4, 6, 8, 10, 12, 14, 16, 18, and 20. Boom, there you go. Math made fun, right?
12 of them.
All multiples of 9 have a final digital sum of 9 as for example 9 times 55 = 495 and 4+9+5 = 18 and 1+8 = 9
44
They are: 64 and 80
it is 83
Even numbers have to end with 2, 4, 6, 8, or 0. And multiples of 5 have to end in 5 or 0.
3 multiples of 4 that is greater than 0 is 8,12, and 16.
The first six positive integer multiples of 55 are: 1 x 55 = 55 2 x 55 = 110 3 x 55 = 165 4 x 55 = 220 5 x 55 = 275 6 x 55 = 330
Multiply each of these numbers by different integers, to get their multiples. For example, the multiples of 4 are:4 x 0 = 0 4 x 1 = 4 4 x 2 = 8 etc.
There are 30 multiples of 4 between 5 and 125. Simply divide by 4 and solve for the multiples of 1 between 1.25 and 31.25. That is a range of 2 to 31, and there are 30 multiples. (31 - 2 + 1)
Multiples of 6 end in 6, 2, 8, 4 or 0.
All multiples of 12 have 3 and 4 as factors, so it would be 12, 24, and 36
-4, -8, -12 and so on.
-45, 0, 45 and 45013590