83, 166, 249, 332, 415 etc.
There are 83 multiples of six that fall between 500 and 1,000.
To find the number of whole numbers between 1 and 500 that are divisible by 6 but not by 8, we need to find the numbers that are multiples of 6 and not multiples of 8. First, we find the multiples of 6 by dividing 500 by 6, which gives us 83 whole multiples. Next, we find the multiples of 8 by dividing 500 by 8, which gives us 62 whole multiples. To find the numbers that are multiples of 6 but not of 8, we subtract the common multiples of 6 and 8, which is 24, from the total multiples of 6, resulting in 83 - 24 = 59 whole numbers between 1 and 500 that are divisible by 6 but not by 8.
200 ÷ 3 = 66 r 2 → first multiple of 3 greater than or equal to 200 is 67 (x 3 = 201) 250 ÷ 3 = 83 r 3 → last multiple of 3 less than or equal to 250 is 83 (x 3 = 249) All multiples of 2 are even, so want all multiples of 3 that are not even, namely the odd multiples of 3; so want 67 x 3, 69 x 3, 71 x 3, ... 83 x 3 which are: 201, 207, 213, 219, 225, 231, 237, 243, 249.
They are all the multiples of 16.They are all the multiples of 16.They are all the multiples of 16.They are all the multiples of 16.
There is an infinite number of possible answers. If you have 83, 83, 83, etc. the mean is 83. If you have 82, 83, and 84, the mean is 83.
The first three multiples of 83 are 83, 166, and 249.
All multiples of 83, which is an infinite number.
Itself and any of its multiples
27
83
83
There are 83 composite numbers.
Between 81 and 84.
There are 83 multiples of six that fall between 500 and 1,000.
Common multiples of 4 and 6 below 1000: Lowest common multiple of 4 and 6 is 12 All multiples of 12 number 83 from 12 upto 996 because 1000/12 equals 83....
Here are the first eight: 12, 24, 36, 48, 60, 71, 83, 95
4 = 2*2 6 = 2*3 Taking the highest power of each prime factor, we can see that common multiples of 4 & 6 are multiples of 2*2*3 = 12 83*12 = 996 so there are 83, starting with 12 (12*1) and going to 996