Well, sugar, if you're trying to be all clever with your numbers, I'll play along. The pattern here is the first few digits of pi: 3.14159. So, the next three numbers would be 2 6 5. Now go impress someone with your newfound math skills, honey.
the next three numbers are 180 540 and 1620=)
64, 125 and 216
Those are the powers of 2, separated by digits. In other words, 1, 2, 4, 8, 16, ... where each number is twice the previous one ... so the next three numbers are 1 2 8.
The next three numbers are: 87, 141, 228. Each number in the sequence after the first two is the sum of the previous two numbers. This is a variation of the Fibonacci sequence which starts with 1, 1, ... (and then continues ..., 2, 3, 5, 8, 13, ...).
Well, judging by the sequence of numbers, the pattern would be to subtract one more than the last time from each new number. Meaning 33-1=32 then 32-2=30 then 30-3=27. The next three numbers would be 27-4=23 and 23-5=18 and finally 18-6=12. So 23 18 and 12 would be the next three numbers in sequence.
the next three numbers are 180 540 and 1620=)
The pattern is multiply by -1, add 5, repeat. The next three numbers are: -7, -2, 2
It appears as if the pattern is doubling, therefore the next three numbers are 16, 32, and 64.
1/5 , 1/25 , 1/125
64, 125 and 216
1 0 0.5 0 0
what are the next numbers in the pattern 1, 2, 3, 5, 8, 13,_,_
12, 13, 16 Add three, then add 1, then add three, then add 1, and so on so forth
The pattern of these numbers is the square numbers. Therefore, following 42 = 16 comes 52 = 25, 62 = 36, 72 = 49.
What numbers would you like to be the next three? It is possible to find a polynomial of order 5 that will fit these three numbers and ANY other three numbers. For example, using the positin to value rule given by Un= -112.275n5 + 1,966.25n4 - 12,744.625n3 + 37,416.25n2 - 48,979.6 + 36,525 I can fit the numbers 1, 2 and 3 as the next three. So there are infinitely many possible answers to the question. Using the simplest rule, although the question does not require that, gives Un = 70n + 2001 and that requires the next three numbers to be 2281, 2351, 2421.
Those are the powers of 2, separated by digits. In other words, 1, 2, 4, 8, 16, ... where each number is twice the previous one ... so the next three numbers are 1 2 8.
The next three are 29, 31, 37.Though technically 1 should not be the first one in the list as it is not a prime number.